# Palindromic Indices solution codeforces

## Palindromic Indices solution codeforces

You are given a palindromic string ss of length nn.

You have to count the number of indices ii (1in)(1≤i≤n) such that the string after removing sisi from ss still remains a palindrome.

For example, consider ss = “aba

1. If we rem ove s1s1 from ss, the string becomes “ba” which is not a palindrome.
2. If we remove s2s2 from ss, the string becomes “aa” which is a palindrome.
3. If we remove s3s3 from ss, the string becomes “ab” which is not a palindrome.

A palindrome is a string that reads the same backward as forward. For example, “abba“, “a“, “fef” are palindromes whereas “codeforces“, “acd“, “xy” are not.

Input

## Palindromic Indices solution codeforces

• Contestants ranked 1st will win a Apple HomePod mini
• Contestants ranked 2nd will win a Logitech G903 LIGHTSPEED Gaming Mouse
• Contestants ranked 3rd ~ 5th will win a LeetCode Backpack
• Contestants ranked 6th ~ 10th will win a LeetCode water bottle
• Contestants ranked 11th ~ 20th will win a LeetCode Big O Notebook

The input consists of multiple test cases. The first line of the input contains a single integer tt (1t103)(1≤t≤103)  — the number of test cases. Description of the test cases follows.

The first line of each testcase contains a single integer nn (2n105)(2≤n≤105)  — the length of string ss.

The second line of each test case contains a string ss consisting of lowercase English letters. It is guaranteed that ss is a palindrome.

It is guaranteed that sum of nn over all test cases does not exceed 21052⋅105.

Output

For each test case, output a single integer  — the number of indices ii (1in)(1≤i≤n) such that the string after removing sisi from ss still remains a palindrome.

Example
input

## Palindromic Indices solution codeforces

Copy
3
3
aba
8
acaaaaca
2
dd

output

Copy
1
4
2

Note

The first test case is described in the statement.

In the second test case, the indices ii that result in palindrome after removing sisi are 3,4,5,63,4,5,6. Hence the answer is 44.

In the third test case, removal of any of the indices results in “d” which is a palindrome. Hence the answer is 22.